4y^2+4y=63

Solution for 4y^2+4y=63 equation:

4y^2+4y=63

We move all terms to the left:

4y^2+4y-(63)=0

a = 4; b = 4; c = -63;
Δ = b2-4ac
Δ = 42-4·4·(-63)
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-32}{2*4}=\frac{-36}{8}
=-4+1/2
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+32}{2*4}=\frac{28}{8}
=3+1/2
$